12m^2+30m+12=0

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Solution for 12m^2+30m+12=0 equation: 



12m^2+30m+12=0

a = 12; b = 30; c = +12;
Δ = b2-4ac
Δ = 302-4·12·12
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$


$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-18}{2*12}=\frac{-48}{24}
=-2
$


$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+18}{2*12}=\frac{-12}{24}
=-1/2
$

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